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The thread: A filter has a selectivity

A cheap stage that proposes candidates for an expensive one is worth having exactly when the candidates are few. That ratio decides everything and appears in no statement of any of these algorithms — and for seed-and-extend it can be computed, before the filter runs, from four numbers that are already known.
pattern of 24, 3 errors allowedpositions in the text20,000candidates proposed140candidates verified140occurrences7pattern 24 · 3 errors · 28,700 cells against 480,000selectivity 5.0% The data that is not a number

The filter that feeds the table

A self-index answers exact queries and nothing else. Approximate matching needs a table with twenty thousand columns in it. The pigeonhole joins them — cut the pattern into k+1 pieces and at least one occurs exactly, and the index that cannot answer the question decides where to ask it.

bits used · answers that were wrongBloom, bits cleared16,384 bits638 said no wrongly · 14 said yes wronglycounting, 4 bits a cell65,536 bits0 said no wrongly · 42 said yes wronglyfingerprints in two slots32,768 bits0 said no wrongly · 153 said yes wronglyand the condition on the caller1,000 deletions of keys never inserted lost 15 that were2,000 keys, 1,000 deleted, 20,000 absent keys querieda false negative is a different kind of wrong from a false positive When the algorithm flips a coin

The evidence a filter cannot remove

A Bloom filter never says no about a key it holds, and that is its whole guarantee. Clear the bits of a thousand deleted keys and it starts saying no about 638 of the thousand it still holds. A counter in every cell repairs it at four times the space; a fingerprint repairs it at twice, and acquires a condition on the caller that neither of the others has.

11010010³10⁴1010010³rows matching the queryblock transfersn/B rows — where the arithmetic says they meetindex, rows scatteredindex, file in key orderread the whole fileB = 64, M = 4,096 (M/B = 64)plus 3 transfers to descend the index When it does not fit

The index that is not worth reading

An index turns a query over 65,536 rows from 1,024 transfers into four. At a thousand matching rows it costs 654 and still wins; at sixteen thousand it costs 1,027 and has lost. Where it turns is decided by the block size — a number the query does not contain, the schema does not mention, and nobody writing either has seen.

queries answered yesabsent key, the AND0.190%absent key, built on the intersection0.025%in one set only, the AND1.800%in one set only, built on it0.000%bits set: A 6,351, B 6,294, AND 3,232, direct 1,859no common key is ever denied When the algorithm flips a coin

The intersection two filters cannot report

Two Bloom filters over sets that share five hundred keys, ANDed bit by bit. The result never denies a shared key, and it looks like a filter of the intersection. It is not one — a key in only one of the sets passes it 1.8% of the time where a real filter of the intersection passes none, and reading the intersection's size off its bits gives 900.

10010³10⁴10⁵errors allowed, kacts01234index walkthe whole table4,000 characters · m = 16 · 4 symbolscrossing at k = 4 What a bound is

The branches an error opens

The tree multiplies by 19.6 for the first error, 12.3 for the second, 10.3 for the third and 8.8 for the fourth. A branching factor of four on a sixteen-character pattern would predict sixty-four, and the gap between sixty-four and eight is the intervals emptying.

k = 0k = 1k = 2k = 3k = 4k = 5k = 6q = 223211917151311q = 3221916131074q = 4211713951-3q = 520151050-5-10q = 6191371-5-11-17q = 81791-7-15-23-31a shaded cell is a threshold of zero or less: every window proposedt = m + 1 − q(k+1) · m = 2411 collapsed cells The data that is not a number

The q-grams an error cannot destroy

A pattern of twenty-four characters holds twenty-one four-grams. Two errors can destroy at most eight of them, so any occurrence with two errors still shares thirteen — and a filter that keeps only the windows sharing thirteen proposes 104 of 3,977 and computes 16,744 table cells instead of 96,000.

10010³10⁴errors allowed, kacts0123index walkthe whole table3,000 characters · m = 20 · 4 symbolsno crossing in range The index that replaces the text

The search that spends a budget

A backward search narrows one interval per pattern character. Give it a budget of three errors and it narrows 39,943 of them instead, finds every occurrence the whole table finds, and reads not one character of the text — 177,046 index ranks against 60,000 table cells and zero characters examined.

0.020.050.10.20.5121235810filter bits a keywasted reads per absent lookupno filters: all 3 levelssame rate every levelrates sized to levelsn = 65,536, size ratio 4, first run 1,024 keysthe same memory at every point When it does not fit

The filter each run carries

A log-structured store turns every lookup for a missing key into a read of every level, and a Bloom filter on each run buys those reads back with memory. Spread five bits a key evenly across three levels and a missing key still wastes 0.279 reads. Give the small levels more bits and the large one fewer — the same memory — and it wastes 0.201. At four levels the gap is 0.382 against 0.209, because sized filters stop the waste growing with the number of levels.

0.01%0.1%1%10%100%1,0002,0003,0004,0005,0006,0007,0008,000keys insertedabsent keys answered yesone filterm = 19,171, k = 7; dotted: the design sizedashed: the design rate When the algorithm flips a coin

A filter past its design size

A Bloom filter sized for two thousand keys at one per cent answers yes to 15.6% of absent keys at four thousand and 68.1% at eight thousand. Nothing fails and nothing warns. A stack of filters that adds a tighter layer whenever the top one fills holds 2.0% at eight thousand, under a bound it can state in advance — in 2.9 times the bits of one filter sized for eight thousand from the start.

100.0010.010.1fraction of the text proposedlog_4 n = 7.101234,56,7seed length, characters · errors allowed abovepattern 24 · text 20,000 · four symbolsrings: the closed form What is taught wrongly

The filter that proposes everything

Seed-and-extend saves two thousand times the work at zero errors and costs more than doing nothing at four. Between them the selectivity falls through the floor, and where it falls is set by two numbers that can be computed before the filter is run — one of which does not contain the length of the text at all.

rank among the boundaries, sorted by the text before themsorted by the text after0 in the rectanglepattern "ss is un"split after 40 end with the left half0 begin with the rightEnglish-like · 2 copies of 512z = 156 · 0 crossing The index that replaces the text

The candidates a filter cannot avoid

A phrase index answers a search by intersecting two ranges of boundaries, and it does the intersection by walking the smaller one. On a collection of thirty-two copies that is 4,355 phrase examinations to produce 32 occurrences — 136 examinations each, and rising.

atgaattcatgagtgacaag00000111111112222222errorsthe pattern, left to right · D belowleast errors neededD, the bound4 symbols · m = 2090 ranks · 2 resets The data that is not a number

The errors the rest of the pattern needs

Read the pattern left to right in an index of the reversed text and count the points where the interval empties. That count is a lower bound on the errors any alignment of the prefix must contain, it costs 72 rank operations, and it removes 70% of a search tree.

0.01%0.1%1%10%100%1,0003,0005,0007,0009,00011,00013,00015,000keys insertedabsent keys answered yesone Bloom filtera stack of Bloom filtersfingerprints, none reservedfingerprints, 3 reservedforecast 2,000, target 1.0%; dotted: the forecastdashed: the target rate When the algorithm flips a coin

A filter that grows by moving a bit

A table of fingerprints can double in place, moving one stored bit of every fingerprint into its slot number, and so grow as one structure with one lookup where a stack of Bloom filters adds layers. Its false-positive rate is fixed by the fingerprint's length and not by the table, so with nothing reserved it doubles as the keys double — 0.69% at a forecast of 2,000, 5.7% at eight times that. Reserve three bits at the start and it holds 0.66% at eight times, in 294,912 bits, exactly what a table built for sixteen thousand keys would hold and fewer than the stack's 428,938. The reserve is a forecast of growth, and past it the rate climbs again.

3579111311.523510positions per key, krate ÷ the independent rateh₁ + i·h₂h₁ + i·h₂, step oddh₁ + i·h₂ + (i³ − i)/6optimal load m·ln 2 / k; one set of hash functions per schemedashed: the account When the algorithm flips a coin

Two hash values and the keys they copy

A Bloom filter that makes its k bit positions from two hash values, as h₁ + i·h₂, answers yes to 1.6% of absent keys on a 64-bit filter where k independent hashes answer 0.69%. The penalty is not the one expected. With the step forced odd no key ever repeats a bit, while a quarter of independent keys do. What costs the filter is a query whose start and step reproduce a stored key's whole progression, which happens with probability 4n/m², measured to within a few per cent from 64 bits to 4,096. The penalty fades as the filter grows and returns as the hash count rises — 1.13 times at seven positions on 1,024 bits, 5.35 times at thirteen.

0.01%0.1%1%10%100%4,00012,00020,00028,00036,00044,00052,00060,000keys insertedabsent keys answered yesfingerprints, none reserved1 bit longer a doubling2 bits longer a doublingfingerprints, 5 reservedforecast 2,000, target 1.0%; dotted: the forecastdashed: the target rate When the algorithm flips a coin

The bits given to the wrong keys

A fingerprint table that gives later arrivals longer fingerprints holds 3.6% where a table that reserves nothing holds 21.1%, and it never runs out of reserve because it has none. It also dies at exactly the same size as the table that reserved nothing — 32 times its forecast, on the same key — because every generation shares one quotient, and the generation with the shortest fingerprint is the one that arrived first.

234681016110size ratioblock transfers · levelsa range of 100 keyslevelsan absent point lookup1,048,576 keys, 5 bits a keyfilters answer one of these two When it does not fit

The read a filter has no key for

A Bloom filter on every run of a log-structured store turns a lookup for a missing key from a read of every level into a fraction of one — 0.72 transfers across eight levels at five bits a key, and 0.00027 at twenty. A range query over the same store reads nine transfers at five bits and nine at twenty, because a filter answers whether one named key is in a run and a range has no key to name.

0%1.1%2.1%3.2%4.2%the whole filterblocks of 64blocks of 5120123456distinct 512-bit lines a lookup readsabsent keys answered yes16,384 bits, 2,048 keys, k = 6one line is what a block buys When the algorithm flips a coin

Positions confined to one line

A Bloom filter lookup reads 5.55 cache lines because its six positions are scattered across the whole filter. Confining them to a 512-bit block makes it exactly one, and costs 7% more false positives at eight bits a key. At sixteen bits a key the same block costs 91%, and the two-value trick that is free across a whole filter costs another 135% inside one — because a block is a small filter, and small filters are where the penalty lives.

8121620240.000010.00010.0010.01bits a keyfalse-positive ratethe whole filterone block of 512 bitsthe emptier of two 512-bit blocksone block of 1,024 bits2,048 keys · 24 filters a pointdashed: no blocks When the algorithm flips a coin

Two blocks and the chances they add

Send each key to the emptier of two 512-bit blocks and the busiest block of a filter at sixteen bits a key holds 38 keys instead of 55. The false-positive rate does not move: 0.100% against 0.095%. At eight bits a key it doubles. A lookup cannot tell which block a key went to, so it has to ask both, and asking twice is two chances to be wrong. The repair that tames a hash table's worst bucket buys a filter nothing that a block twice as wide does not.

0.010.11errors allowed, kshare of windows proposed01234q = 3q = 4q = 5a shaded dot is a collapsed thresholdm = 24 · n = 4,000 · 6 planted1 collapsed rows What is taught wrongly

The threshold that reaches zero

At q = 5 and four errors on a twenty-four-character pattern the filter demands zero shared q-grams, proposes all 2,977 windows, and computes 986,266 table cells where filling the whole table would have cost 96,000. The failure is arithmetic and is knowable before a character is read.

the whole table60,00060,000r · 0rkcounting filter24,84315,369r · 0rkseed filter17,7452,415r · 1,377rkindex walk00r · 177,046rkn = 3,000 · m = 20 · q = 4cells drawn · r = characters read, rk = index rankscells computed6 occurrences What is taught wrongly

Three savings in three currencies

The same six occurrences, found four ways. The table computes 60,000 cells and reads 60,000 characters. The counting filter computes 6,251 cells and reads 13,022 characters. The seed filter computes 3,325 and reads 550. The index walk computes none, reads none, and performs 18,645 ranks.

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