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The thread: Measured, not assumed — page 8

Page 8 of 14, continuing the same thread in the same order.
00.50011.50arcs redrawn between queriesstored potential ÷ Bellman–Ford per query0.02%0.1%0.5%2%5%20%recomputed from nothingmended from the broken arcs256 vertices, 128 queriesarc costs redrawn Two parameters

A potential mended where it broke

A stored reweighting on a 256-vertex graph with negative arcs costs 10,045 relaxations to rebuild, and rebuilding it every time an update breaks it stops paying once half a per cent of arcs change between queries. Mending it from the arcs that broke costs 16 to 442 relaxations instead, and the stored potential stays at two thirds of the per-query cost at every rate of change. When the change is a vertex whose costs all move together, a repair reaches nearly every vertex. It still costs a third of a rebuild.

0%25%50%75%100%8101214161820222426283032bits of key prefix the filter is built onshare of the empty levels the filter skips83%72%64%46%ranges of 0.1 keysranges of 1 keyranges of 10 keysranges of 100 keys5 bits a key, 4 levels, 2,000 ranges eachdigits: the best length's share When it does not fit

The runs a range query can skip

A Bloom filter over key prefixes can tell a range query that a run holds nothing it wants, which a filter over keys cannot. On a four-level store of a million keys, a range expected to hold one key costs 4.76 transfers with no such filter and 2.41 with one built on 20-bit prefixes. The best length moves two bits for every tenfold longer range. By a hundred keys the most any range filter could save is a fifth of a transfer, because only the smallest level is ever empty. And the same memory spent on 20-bit prefixes makes a lookup for an absent key three times dearer.

1,00010010³10⁴10⁵10⁶keys sortedcache missesno recorda cache of 1,024 pairsthe table, written twicethe table, by ordered pairselection sort, 512 lines of 64 bytesexact LRU Counting

The record measured where it would run

A table of every pair selection sort has compared saves half its comparisons at 1,024 keys, and priced in word operations it was the better record at every size. Replayed through a 32 KB cache it misses 477,824 times to save 258,290 comparisons — nearly two misses for every comparison it removes — while a cache of 1,024 pairs misses 192. The table's size is not the problem. Its layout is: it looks up and writes each question at [key][minimum], a new row every time. Indexed by the ordered pair instead, the same bits miss 3,079 times, and that repair works only for a sort whose smaller operand stays put.

00.0200.04000.1000.200positions in a repeated 16-character stringexcess at 8 characters, bits a symbolthe corpus of technicalwriting, r = 0.98the corpus of essays, r = −0.37one point a streamcontext of 8 characters The floors

The repeats a context cannot see past

Sorting rotations by their first k characters stops losing to the full Burrows–Wheeler transform at four or five characters on four sources and at about ten on a corpus of technical writing. The count proposed to explain the exception — how much a context spanning a word boundary says about the letter before it — cannot be read off its own estimate, which falls on words drawn independently where there is nothing to find. Measured against each text's own shuffled twin, the information the word order carries is real, but it has all arrived by four or five characters, and at eight, twelve and sixteen the two corpora are indistinguishable. What does separate them is repetition. Stream by stream, the share of positions inside a repeated sixteen-character string predicts the technical corpus's loss with a correlation of 0.98.

0.310.621.242.484.859.7the rise's offset in d, in spreads of dreadings that alarm0%5%25%50%75%100%held while alarmedthe positive clockcorrected for the slopesolid: R = 16; dashed: R = 64dashed rule: a still stream's 5% One pass, and no room

The slope the slow counter already shows

A burst detector built from a fast and a slow decayed counter reads a steady rise in its background as an offset in their difference, β(R − 1)H/ln 2, and alarms on it. Every repair so far waited the offset out. This one subtracts it: the slow counter's own change over one slow half-life is a reading of the slope, and the offset follows from it. At R = 16 the corrected detector alarms on 5.5% to 7.8% of readings on rises that make the held scale alarm on 11% to 63%, and it costs a burst at most 3.7 seconds of detection. The estimate has to be quick: four times slower, it has recovered only 71% of the offset when alarms start to count.

whole listthree commonestcommonestone, counts unread0%50%100%3–4 letters83%64%5–6 letters95%83%7–8 letters99%95%9–10 letters99%99%11+ letters100%97%streams drawn by use; misspellings of vocabulary wordsties shared by expectation When the algorithm is a table

The commonest word at the distance

A spelling checker that lists every nearest word counts a correction whenever the intended word is somewhere in the list, and on a short query that list averages three or four words. Offering only the commonest of them was predicted to keep nine in ten of the list's corrections on short words when misspellings follow use, and far fewer when they are drawn evenly from the word list. It keeps 77% on words of three or four letters, and on the even stream it keeps 48% — less than a choice that ignores the counts. Across all lengths the two streams look the same, which is how the difference stays hidden.

02468101214mean 5.71depthshare of the collectionten revisionstwelve essays75,658 characters · 2,966 phrasesworst 14, mean 5.71 The data that is not a number

The shape of a real history's depth

Four essays here are about capping how far an extraction follows a chain of copies, and every number in them came from a generated collection. Here is the depth histogram of a real version history, which is a bell, and of twelve unrelated essays, which is nearly the same bell.

0.50011.5020102030cells the destination moved from the one the landmarks were fitted tocells expanded, fitted placement ÷ cornersthe corners0/87/4811/4825/4832/4834/4841/4842/48digits: cases worsethan the corners8 maps, 6 directions a distancebelow one the fit is still worth having Two parameters

A placement after the traffic moved

Four landmarks fitted to twenty queries that all end at one cell expand two thirds of the corners' cells there. Move the destination ten cells and the advantage is gone; move it thirty and the fitted placement expands nearly twice the corners' cells. Choosing again costs 317,000 cells of search — the saving of 8,600 queries — so on streams whose destination drifts, a policy that refits on a counter never beats fitting once and keeping the result, and past a drift of about ten cells nothing fitted beats the corners.

2122232451015pages written per key insertedleaves in the finished tree, in hundreds1241664target 1target 2target 8fixed reach (digits:siblings)reach following the walks131,072 keys, leaves of 64, fan-out 64window of 64 overflows When it does not fit

A reach that follows the stream

A full B+-tree leaf that passes keys along its siblings wants a short reach on random insertion and the whole parent on a nearly ordered stream, and a tree is never told which it is receiving. Let the reach double after every 64 overflows whose walks averaged two siblings or less and halve otherwise, and it finds the whole parent on every ordered stream. On random keys it lands on the fixed reaches' own frontier. On a stream that turns from random to ordered halfway it beats every fixed reach, by 57 leaves at the same writes. It notices a turn to random in 62 insertions and a turn to order in 779. Below a target of 1.75 siblings it thrashes on ordered keys.

11010010³0.00010.0010.010.1keys held, as a multiple of the forecast of 2,000share of absent keys answered yesthe 1% targetten bits reservedrebuilt from the storerebuilt only when it cannotgrowa stack of Bloom filtersforecast 2,000 at 1%, grown to 2,000,00020,000 absent keys a point When the algorithm flips a coin

The day a filter cannot grow

A fingerprint table dies when its quotient reaches its shortest fingerprint, and a filter cannot lengthen a fingerprint because it does not keep its keys. The store it filters does. Rebuilt from that store whenever its own count says its rate has passed 1%, a table grown a thousandfold never exceeds 1.05% and ends holding exactly what a reserve of ten bits holds — 18.9 bits a key — having read the store 1.34 times over. The reserve paid its bits early: 34.8 a key at four times the forecast, where the rebuilt table held 18.4. Which one is cheaper depends on whether the growth arrives.

4-bit2.97× · mean 2.426-bit2.23× · mean 1.828-bit1.50× · mean 1.2211-bit3.61× · mean 1.5916-bit7.73× · mean 3.23from the counts1.23× · mean 1.06the best for each caseworst over 4 inputs × 2 cachesmisses ÷ the best fixed width's Counting

The digit a pass chooses for itself

A radix sort's digit width trades passes against the streams each pass scatters into, and the best width depends on the keys and the cache together: 8 bits for uniform keys through 32 KB, 11 through 256 KB, 16 for keys with few distinct values. A digit widened because the previous pass's counts were concentrated cannot find it, since in a least-significant-first sort one digit's counts say nothing about the next. One read that counts every byte at once, and a sample to size each field, can. Charged for both, the resulting plan is never worse than 1.23 times the best fixed width on any keys or cache measured. The best single fixed width reaches 1.50, and 11 bits reaches 3.61.

2.802.9033.1040506070characters read a symbolbits a symbol after move-to-frontsorted by 2sorted by 4sorted by 8by 2, deepenedby 4, deepenedby 8, deepenedthe full transformeight streams of 8,192 charactersthe corpus of technical writing The floors

The deepening the sort was already doing

A sort of rotations by their first k characters loses to the full Burrows–Wheeler transform where a longer string repeats, and a sort deepened only inside the ranges where contexts repeat was proposed to recover those bits at a fraction of the transform's reading. It recovers the bits: on sixteen streams every one lands within 0.006 bits a symbol of the transform, and the most repetitive goes from 0.129 bits worse to 0.001. It reads more characters than the transform, not fewer — 74.5 a symbol against 69.4 on technical writing — because a comparison sort of rotations already reads deep only where rotations agree. The transform was the adaptive sort. The characters a sort by k characters saves are exactly the ones the repeats needed.

-2-1012305001e+3seconds from the end of the risemean difference, in spreads of dthe rise endsuncorrected, 20% risecorrected, 20% riseuncorrected, 40% risecorrected, 40% risemean of 24 streams, R = 16zero: the background's own level One pass, and no room

The rise the correction kept subtracting

A burst detector that subtracts a rising background's offset, read off its own slow counter, goes on subtracting it after the rise has stopped. The prediction was a deficit for about one slow half-life that would cost bursts of 300 arrivals. Measured, the deficit is deeper and longer: down to 1.46 spreads below zero, below half a spread for seventeen minutes after a 40% rise. Bursts of 300 are never missed. What the deficit costs is small bursts — 30 arrivals caught 27% of the time where the rise saw 77% — and a fifth of a large burst's visible time.

0.7000.80011.251.501.752words shown, mean over answered queriesshare of misspellings correctedonetwothreer 10fixed listsratio rule, three in doubtratio rule, two in doubtone word or three, mixed3–4 letters, drawn by useexpected credit, ties shared When the algorithm is a table

A list as long as the doubt

A spelling checker that offers one word is right 64% of the time on short misspellings, and one that offers three is right 80% of the time. Between them sits the obvious design: one word when the commonest nearest word's count dominates the next, more when the counts are close. The counts do know when the commonest word is right, from 36% of the time at a ratio under two to 91% over a hundred. Yet a list sized by that ratio beats a blind mix of one word and three by at most two and a half points, a plain list of two does as well, and on misspellings drawn evenly from the word list the ratio is worse than not reading it.

1001,00010characters in the wordruns · phrasesr, worse orderz, either orderr, better orderFibonacci words · two symbolsspread 1.50x to 3.17x What is taught wrongly

The measure that cannot see the alphabet

Take a Fibonacci word of 4,181 characters and transform it with a before b — six runs. Transform the same word with b before a — nineteen. The parse gives eighteen phrases either way, and the gap between the two run counts grows with every word in the family.

05101520510revisions in the collectiondepthone revision alone: 8worst depthmean depthfourteen revisions of another9 generations added exactly one Structures

One revision, one level

The cap ladder assumed depth is generations of copying. On a real file it is exactly that — one more revision, one more level, nine times running — plus eight levels the first revision already had before any history existed.

one text16 short documentsprosecopies of one baseprose, one textr/n 0.2996z/n 0.1273prose, many short documentsr/n 0.3053z/n 0.1301copies of one base, run togetherr/n 0.0638z/n 0.0354one copy per documentr/n 0.0768z/n 0.04188,192 characters throughoutthe outlined cell is the one that was empty The data that is not a number

The cell nobody filled

Every structure here was measured either on one long repetitive text or on prose cut into short documents. The collection that is both is a two-by-two with one empty corner, and what is in it is not the product of its margins.

0100200cells a query, selections included2,5005,00010,00030,00012.3 jumps6.2 jumps3.5 jumps0.8 jumpsmean queries between jumps, and jumps a streamthe corners, never fittedfitted once, keptfull refit on the counterone landmark, on the counterone landmark, every 5,0006 maps, 30,000 queries a streamcounter: window 2,000, threshold a half Two parameters

A refit that changes one landmark

Choosing four landmarks again after traffic moves costs hundreds of thousands of cells of search, and on drifting streams it never paid. Keeping three and re-choosing the fourth costs a fifth as much — 0.19 of a full selection, not the twelfth the earlier page guessed. On drifting streams, refitting on the counter goes from a loss of up to 13% to within 2% of fitting once, and it wins where the destination moves six cells. When the destination jumps, it is the cheapest policy measured, 12% under the corners at one jump in 10,000 queries — unless the jumps come as often as one in 2,500.

10,000100,000keys in the filtershare of absent keys answered yes0.04%0.05%0.06%0.08%0.10%the emptier of twoone blockone block, Poisson averageone block, by threshold16 bits a key, 512-bit blocks2,000,000 absent queries a point When the algorithm flips a coin

A penalty set by the block

A blocked Bloom filter pays a penalty for its uneven block loads, and a threshold that lets a lookup work out its block repays about a third of it — measured on 2,048 keys, with a prediction that larger filters would widen the gain. From 2,048 keys to 131,072 nothing moves: one block holds 0.086% to 0.090% against a computed 0.086%, and the threshold design 0.060% to 0.065%. The busiest block grows and the rate does not follow it. What sets both the penalty and the repair is the keys a block holds. A threshold turns out to be worth one doubling of the block's width, and its advantage shrinks from 40% at sixteen keys a block to between 5% and 13% at 128.

235810filter bits a key, averaged over the storetransfers a query3.804.204.605.00one length, even bitsa length each, even bitsa length and bits eachthe oraclemixed workload, 2^20 keys, four levelsdotted: the oracle When it does not fit

The small levels' share of a range filter

Prefix filters on a four-level store were proposed a prefix length each, on the reasoning that one length is a compromise between levels whose densities differ 43-fold. Each level does want its own length, 18 to 22 bits, and that recovers a quarter of the gap to a perfect range filter. The gap is mostly not about length. Three fifths of it is false positives. Moving filter bits from the largest level to the small ones — 12, 12, 8 and 3 bits a key instead of 5 each — recovers more than half of it at the same memory, and matches one shared length given twice the memory.

1248163264rows in the ringshare of the table's skipped comparisons0%25%50%75%100%256 keys1,024 keys2,048 keysselection sort, random keysticks: expected minima a pass Counting

A record the size of a pass's minima

Selection sort's table of every pair it has compared is 256 KB at 1,024 keys, and indexed by the ordered pair it lives almost entirely in the rows of the current minima. Keep only those rows — a ring of r rows, the least recently used given up — and 12 rows, 3 KB, catch 99% of the comparisons the whole table skips, with no misses beyond the first touch of each row. The ring beats the cache of 1,024 pairs on both axes at once. The rows it needs grow with the logarithm of the input, a few more than the minima one pass passes through, and which row it gives up matters as much as how many it has.

the corpus of technical writing0.000.010.020.0355606570the corpus of essays0.000.010.020.03556065characters read a symbolbits a symbol above the transformolive: longest first · dark: most different · green: transformeight streams of 8,192 characters eachrotations first sorted by four characters The floors

The order the column cannot see

A sort of rotations by their first four characters leaves ranges that agree on those four, and the full Burrows–Wheeler transform reads deeper to order them. Given a budget of characters below the transform's, spending it on the ranges whose rotations are preceded by the most different characters was predicted to reach within a hundredth of a bit at two thirds of the transform's reading — and spending it on the longest agreements, as the transform does, to waste it. The price was impossible: the four-character sort alone reads 76% of what the transform reads. The ranking was right on average, and right for a reason that makes the budget unnecessary: a range whose rotations are all preceded by one character writes the same run into the output in any order. Skipping every such range writes the transform's column exactly, on all sixteen streams, and reads 11% less on technical writing — up to 19% on the stream with the longest repeats.

501002005001,0002,0005,000Zipf exponent of the stream (0 is flat)words for 10% on F3 (log scale)00.250.50.7511.52sample every positionshare 3%, list of 64share 1%, list of 8the best fixed list60,000 arrivals, 2,048 keysa word: a key or a count One pass, and no room

A share of a list of equals

Estimating the third frequency moment by finding the heavy keys first and sampling the rest works best with one counted candidate on steep streams and sixteen at Zipf 0.5, and a system that does not know its stream's skew has to pick. Keeping a long list and counting a candidate only if it holds a stated share of the list's own moment was predicted to come within a few per cent of the best fixed list on every exponent. The share does choose: at 3% it keeps one candidate at Zipf 2, three at Zipf 1, five at Zipf 0.5. But a list the stream shortens is not a short list. Its sixty-four candidates cost 192 words on every stream, four times the whole of the best estimator on the steep ones. On a flat stream every candidate is a near-equal share of a list of equals, and no share can tell that none of them is heavy. No list length and share comes within 10% everywhere; at Zipf 0.5 alone, the chosen list beats every fixed one.

6570758011.251.501.752words shown a querycorrected, % of words of 3–4 lettersone wordtwo wordsthreeshare ruleratio rulecoin's lineε = 0.01up and left is better When the algorithm is a table

A second word judged by its own share

A spelling checker that offered its commonest nearest word alone when that word's count was many times the next, and two or three words otherwise, beat a coin's mix of one-word and three-word lists by at most two and a half points, and a plain list of two did better. The ratio measures how dominant the first word is, not how likely the second is. Judged instead by its own share of everything within two edits of the misspelling, the second word is shown only when that share is at least 0.15: on short words drawn by use the checker then sits 4.5 points over the coin's line at 1.32 words a query, nearly twice the ratio's lift and above the list of two, and the weight given a two-edit word moves the result by a tenth of a point. A second word with a share under 0.01 is never the source. On misspellings drawn evenly the share is no guide at all, and the list of two wins.

0.010.11errors allowed, kshare of windows proposed01234q = 3q = 4q = 5a shaded dot is a collapsed thresholdm = 24 · n = 4,000 · 6 planted1 collapsed rows What is taught wrongly

The threshold that reaches zero

At q = 5 and four errors on a twenty-four-character pattern the filter demands zero shared q-grams, proposes all 2,977 windows, and computes 986,266 table cells where filling the whole table would have cost 96,000. The failure is arithmetic and is knowable before a character is read.

73 characters long24 runsto depth 7270 characters long24 runsto depth 69longest: 73 × "-" at position 11,0162,685 positions below depth 20, 2,685 of them inside a runeight source modules · worst depth 78100.0% in runs What is taught wrongly

The deepest text is punctuation

Eight source files reach depth 78 in a parse, on a collection with no version history in it at all. The positions between depth 20 and depth 72 are the same 48 characters at every level, and every one of them is a dash in a comment separator.

10⁴0.1charactersphrases of the parse, per charactershuffled: 1.45xthe collection: 4.71x4,111 to 65,551 charactersworth 3.24x after the control The data that is not a number

What repetition is worth once the logarithm is gone

On prose, nearly three quarters of the fall in phrases per character with size is arithmetic that any text pays. On a collection built of copies it is a fifth, and what is left is a factor of three that is genuinely the arrangement.

11.051.101.15price, as a share of a full selectionfresh queries' cells against all candidates00.050.100.150.200.252 nearest4 nearest6 nearest8 nearest12 nearestall 2424 refits, 4 mapsdashed: the unrestricted refit Two parameters

The candidates near where the queries end

Re-choosing one landmark after the traffic moves tried every candidate as the replacement, and most of them could not win. Tried only on the four candidates nearest the new destination, the refit costs 0.085 of a full selection — the twelfth an earlier page guessed — against 0.236, and its placements serve fresh queries within 3% as well. Where the full search's winner lies further away, the refit was barely worth making. A refit that cheap still cannot follow a destination that jumps every 2,500 queries; what holds the counter back was never the refit's price.

0.00%0.05%0.10%0.15%256 bits · one block0.148%256 bits · a threshold on the first0.089%256 bits · thresholds on both0.095%512 bits · one block0.089%512 bits · a threshold on the first0.062%512 bits · thresholds on both0.066%1024 bits · one block0.066%1024 bits · a threshold on the first0.058%1024 bits · thresholds on both0.052%with no spreadwhat the spread adds16 bits a key, 8,192 keysno spread: every block at its mean load When the algorithm flips a coin

The bits a second threshold costs

A blocked Bloom filter whose first block carries a threshold was proposed a second threshold on each key's second block, with a third block for keys both refuse. It does what it was meant to: at 512-bit blocks it removes nearly a third of the load spread the first threshold left. And the rate does not fall — 0.066% against 0.062% — because the second table, paid for in blocks, raises the rate the filter would have with no spread at all by more than the narrower spread saves. The threshold was stored in more bits than it needs: at four to six bits, one threshold beats the eight-bit design by about a tenth on one run, and a second threshold of the best width ties it at 512-bit blocks.

1282565121,0242,0484,096keys sorted, ntable's skips caught94%96%98%100%the chain of the last passa ring of twelve rowsrandom keys, every answer checkedring: the earlier record, LRU Counting

A record of stretches, not pairs

Selection sort asks many of its comparisons again, and a record of past answers can skip them. A table of every pair skips them all in 256 KB at 1,024 keys, and a ring of the recent minima's rows in 3 KB. The questions a pass repeats have more structure than rows record: each minimum of the previous pass was compared with one contiguous stretch of positions. Kept as a list of stretches — each minimum's position, where its stretch began, and where the key that beat it stood — the previous pass's chain answers 99.3% of what the table would, in 312 bytes. The failure predicted for it, a key the swap moves into a stretch, costs 0.04%. What the chain cannot do is stay small on every input: on reversed keys it needs a link for every key.

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