Sparse graph — where it appears
Named by 6 essays across one field — each of them below, with the objects they name alongside it.
Counting on a graph
An instrumented array counts comparisons, swaps, reads and writes, and none of those is what a graph algorithm spends its time on. Three new primitives are needed — an adjacency scanned, a vertex first reached, an edge relaxed — and once they exist, breadth-first and depth-first search turn out to be the same algorithm by every count kept on arrays.
Two parameters, one bound, no order
With one size parameter the candidate classes are ordered — n beats n log n beats n², always, and comparing two bounds is reading them. With two, E log V and V² have no order at all, and which one is smaller is a property of the graph. Sweeping V at fixed degree and at fixed density are different experiments, and the same algorithm fits different classes in the two.
The queue decides the class, and the pseudocode does not name it
Dijkstra's algorithm is eleven lines of pseudocode with a priority queue in the middle of them. Which queue is not stated, and it is the difference between 56,973 units of work and 2,118,656 on the same graph. Two of the three queues here also fail to fit the class they are famous for, in a regime each.
Two parameters are not enough either
Two graphs on 1,024 vertices with 3,072 edges each — identical in both numbers every bound in this field is written in. Enumerating every pair of neighbours of every vertex costs 18,480 examinations on one and 42,076 on the other. The quantity that separates them is a third parameter, it is computable in linear time, and it appears in no statement of the problem.
The bound with a precondition
Bellman–Ford is O(V·E), and on a graph of 2,048 vertices it stops after seven passes of the 2,047 the bound allows — a factor of 289 between the bound and the run. Dijkstra is faster and returns a wrong answer on four vertices if one arc is negative. Both facts are about the same clause: the qualifier at the end of the sentence.
A bound right for the wrong reason
Orient every edge of a graph towards its higher-degree endpoint and count triangles among out-neighbours, and the work is O(E·d), where d is the graph's degeneracy. The usual reason given is that the orientation keeps every out-degree at most d. On a graph of 1,024 vertices with degeneracy four, 136 vertices have more than four out-neighbours and one has seven. The bound survives by a different argument, and the orientation that does keep every out-degree at most d does less work.
Named alongside it
The objects these essays reach for when they reach for this one.
Dijkstra's algorithmAdjacencyCounted primitiveDensityWorst caseDegeneracyDegree distributionHeapHonest limitMeasured countOrientationPreferential attachment