Concept

Exhaustive search — where it appears

Walking every case of a finite space rather than sampling or arguing about it. It gives certainty at a size a figure can draw and no formula, which is the trade every counting floor in this collection makes.

Named by 10 essays across 2 fields — each of them below, with the objects they name alongside it.

10110100runs in the transform, rbitsthe structurelog₂ N(r)12 characters · 2 symbols · all 4,096 texts walkedgap 14.1x–92.0x

A floor under a run count

A structure whose size is a function of the number of runs in a transform must give a different bit string to every text with that many runs, so it needs at least the logarithm of how many such texts there are. That count is walked rather than estimated — all four thousand and ninety-six of them — and the representation everybody uses turns out to have five bits of slack.

floors · Repeat
SETHno algorithm for k-SAT beats exhaustive search for every korthogonal vectorsno N^(2-e) algorithmedit distanceno n^(2-e) algorithmperformed heresplit and list, checked on 55,754 formulasquoted, not performed herequoted, not performed heresolid: an implication performed here · dashed: one that is quoteda conditional floor

A floor that holds if something else does

The four lower bounds on this site are proofs. This one is a chain of implications with a conjecture at the top, and neither end of it is proved. The link that can be performed is performed here — checked over 55,754 formulas, 918 of them unsatisfiable — and the link that cannot is quoted and marked as quoted.

floors · Bound
every orderthe named inputsmean0102030comparisonsInsertion sort7 to 28 · named inputs reach 28Merge sort12 to 17 · named inputs reach 16Heapsort21 to 29 · named inputs reach 27Quicksort, first-element pivot13 to 28 · named inputs reach 28Quicksort, median of three25 to 29 · named inputs reach 2540,320 orders of 8 distinct elements3 worst cases unnamed

A count over every input

Run five sorts on every one of the 40,320 orderings of eight elements and read off each one's best, mean and worst comparison count. Then mark where the inputs a benchmark generator names — sorted, reversed, nearly sorted, random, few unique — land. For merge sort, heapsort and quicksort with a median-of-three pivot, the worst case is an ordering none of them produces, and for the last of the three every named input lands on its best case.

counting · Count
40%60%80%100%8121624324864elements sortedshare of the known worst case the climbs reach, on averageInsertion sort · 20 of 24Merge sort · 24 of 24First-element quicksort · 0 of 24hollow: none reached it24 climbs a size · 100 swaps per elementworst cases known exactly

The worst case found by climbing

A search that swaps two elements at a time and keeps whatever does not lower the count finds the worst case of all five sorts at eight elements, where every answer can be checked. At sixty-four it finds merge sort's worst case every time and reaches 39% of first-element quicksort's — whose worst case is sorted input, the most famous bad input there is. Checking a search where the answer is known certifies it only there.

counting · Count
0.0010.010.11125102050fraction of positions reshuffled, pmean comparisons, in multiples of the mean on random inputFirst-element quicksort, 81.9×Median-of-three quicksort, 41.4×Insertion sort, 2.0×Merge sort, 1.0××: unshuffled2,048 elements · 12 shuffles a point1 = the mean on random input

A worst case ten positions wide

Sorted input costs first-element quicksort 2,096,128 comparisons on 2,048 elements, 82 times its average. Reshuffle about eleven of the 2,048 positions and the cost halves — and it takes about ten at 128 elements, and between ten and thirteen at every size between. Reversed input costs insertion sort twice its average, and reshuffling half the positions still leaves 71% of the work. A worst case is a place in the space of inputs, and the two famous ones are places of very different sizes.

counting · Count
0102030comparisons on one orderingfloor 16Insertion sort7 to 28 · mean 19.28Merge sort12 to 17 · mean 15.73Heapsort21 to 29 · mean 25.81First-element quicksort13 to 28 · mean 16.92Median-of-three quicksort25 to 29 · mean 26.30Batcher's network19 on all 40,32040,320 orders of 8, enumeratedfloor ⌈log₂ 8!⌉ = 16

The sort whose count has no distribution

Batcher's network makes nineteen comparisons on every one of the 40,320 orderings of eight elements — sorted, reversed, adversarial or random — because it decides which pairs to compare before it sees any of them. That is two above merge sort's worst case and four below heapsort's best. At 65,536 elements the same refusal to adapt costs 4.07 times merge sort's worst case, and it buys three things no adaptive sort has, one of which is a proof of correctness that takes 65,536 inputs instead of twenty trillion.

counting · Count
probe 1: 0–1 absent9 still to ask10 of 10 as good as anyprobe 2: 0–2 absent8 still to ask9 of 9 as good as anyprobe 3: 0–3 absent7 still to ask8 of 8 as good as anyprobe 4: 0–4 present6 still to ask7 of 7 as good as anyprobe 5: 1–2 absent5 still to ask6 of 6 as good as anyprobe 6: 1–3 absent4 still to ask5 of 5 as good as anyprobe 7: 1–4 present3 still to ask4 of 4 as good as anyprobe 8: 2–3 absent2 still to ask3 of 3 as good as anyprobe 9: 2–4 present1 still to ask2 of 2 as good as anyprobe 10: 3–4 absentdecided1 of 1 as good as any5 vertices · 10 pairs · 59,049 states solvedsolid: present · dotted: absent · coloured: this probe

Every pair must be asked

Ask whether a six-vertex graph is connected, one pair of vertices at a time, and the best possible algorithm needs all fifteen questions on its worst graph. The claim that this holds for every monotone property of graphs is a conjecture fifty years old. At four vertices it can be settled completely: all 2,046 properties that do not depend on vertex names need every pair. Name one vertex, and the count drops from ten to four.

floors · Floor
1416642561k2k4k8k16k33k66k11010010³10⁴10⁵10⁶keys handed backcomparisons no method can go underthe losers, and the outputs' ownorderevery element not handed back losesthe answer is one of n!/(n−k)!sequences65,536 keyseach is a claim about every possible method

Two floors that can be added

Handing back the ten smallest of 65,536 keys has two floors under it and neither is close where they cross — the larger of the two is 63,821 comparisons at k = 4,000 and the best method makes 125,401. They can be added, because a comparison that eliminates a key the caller never sees can never be a comparison that orders two the caller does see. Charged together the floor rises 62%, and the tournament goes from 1.97 times it to 1.21.

counting · Count
length of the longer list, nshorter, m1234561234561floor 12floor 22floor 23floor 33floor 33floor 33floor 34floor 45floor 45floor 56floor 55floor 56floor 67floor 67floor 77floor 78floor 79floor 89floor 810floor 911floor 10the optimum is one above the floorthe floor is reachedevery cell solved exactly · m ≤ n ≤ 6large: the optimum · small: ⌈log₂ C(m+n, m)⌉

The floor a merge cannot reach

Merging two sorted lists of five keys each has 252 possible outcomes, so counting says eight comparisons might do. Solving the game says nine are needed, and on equal lengths the shortfall keeps growing, as half the logarithm of the length. Averaged over random inputs, though, the same count is missed by a tenth of a comparison. The counting floor is nearly exact on average and wrong in the worst case.

floors · Floor
11010010³10⁴10⁵10⁶k, the number handed backcomparisonstournament, measuredfloor that names the outputsbest earlier floorn = 65,536, one shuffled inputthe floors are worst-case, the count is one input

The comparisons that name the answer

Returning the 4,000 smallest of 65,536 keys in order needs 61,536 comparisons to eliminate the rest and 42,100 to order the ones returned. That was the floor, 103,636, and a tournament made 125,388. What the floor never charged is saying which 4,000 come back. Charge that, and the floor is 125,341. On the same input the tournament is 47 comparisons above it, and for every k up to a hundred it is exactly on it.

counting · Count

Named alongside it

The objects these essays reach for when they reach for this one.

Worst caseLower boundComparison countHonest limitMerge sortAdversary argumentHeapInformation floorAdversarial inputBenchmark inputCounterexampleFalsification

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