Pareto frontier — where it appears
Named by 7 essays across 4 fields — each of them below, with the objects they name alongside it.
Choosing a growth factor
When a dynamic array fills up, how much bigger should the new one be? Doubling costs 2.02 units per append and leaves 39% of the allocation empty. Growing by an eighth costs 9.89 and leaves 10%. Every factor is a trade between time and space, no factor wins on both, and real implementations disagree about the answer for reasons that are measurable.
The frontier between time and space
The question of which sorting algorithm to use has an honest answer, and it is a shape rather than a name. Comparisons on one axis, peak auxiliary space on the other, and five of the ten algorithms here are on the Pareto frontier while five are dominated — beaten on both counts at once, so that no weighting of the two costs makes them the right choice. Heapsort is one of the five that lose.
The count somebody chose
Six quantities can now be measured for every sort. Ranking the ten algorithms by each of them and comparing the orders, comparisons and peak space disagree about 91% of all pairs, and memory traffic and modelled misses disagree about 7%. There is no ranking of sorting algorithms; there are six, and choosing between them is a statement about the data rather than about the algorithms.
The space the model does not see
A slot is not a byte, a frame is not a slot, sixteen thousand allocations are not one allocation of the same size, and none of these numbers includes the input. The space counters are the newest instrument here and the honest account of what they miss is longer than the account of what they measure — including one bound this phase set out to demonstrate and could not.
Every occurrence at the same price
A regular sampling has one dial and it moves two costs together — 1,495 bits at 63 LF steps an occurrence, 131,088 bits at none. A sampling at the run boundaries sits at 10,244 bits and one predecessor query, which is a point the curve reaches only at 69,649.
What a ceiling costs in phrases
A cap of sixteen costs one phrase of a hundred and fifty-six and halves the worst chain. A cap of four costs six times the phrases. The curve between them is flat at one end and vertical at the other, and the elbow is where a structure should be built.
The shape one structure will not fold
Folding thirty-two shards largest-pair-first keeps 2,556 quantile tuples against a balanced tree's 3,211 — a fifth of the space saved. The same fold on the counter tables beside them leaves 403 counts of error against the tree's 148. A deployment holding both cannot fold once and be right twice.
Named alongside it
The objects these essays reach for when they reach for this one.
Trade offCacheDominanceMeasurementQuicksortTime space tradeoffAllocatorAuxiliary spaceCost modelGrowth factorIndex sizeRanking